4(t^2-2t)=3t^2-16

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Solution for 4(t^2-2t)=3t^2-16 equation: 



4(t^2-2t)=3t^2-16

We move all terms to the left:

4(t^2-2t)-(3t^2-16)=0

We multiply parentheses

4t^2-8t-(3t^2-16)=0

We get rid of parentheses

4t^2-3t^2-8t+16=0

We add all the numbers together, and all the variables

t^2-8t+16=0

a = 1; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{8}{2}=4$

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